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BitBanger
February 14th, 2003, 14:01
Hello,

I encountered the following problem when using bpx type breakpoints in SoftIce. When setting this kind of breakpoint in some applications program generates exception (execution of int 3 instruction) and is terminated when program flow reaches the address of bpx. Then when i remove bpx in SI by bc command and run the program again, the int 03 instruction is still at address of previous breakpoint even after I removed it in SI and stays there until i reboot the system (i did not yet discovered how to remove this int 03 instruction without reboot). My question is: Is this behaviour caused by the protection of the application which detects breakpoints and "patches" the program or is it problem of some other kind?

Thank you for your help.
BitBanger

JMI
February 14th, 2003, 15:20
BitBanger:

Since this is your first post and it raises a subject discussed several times before, it would appear that you did not follow your instructions to Read the FAQ (Frequently Asked Questions). Among the advises you would receive there is that you should do a search, using the search button at the top of each Forum to attempt to determine whether your question has been asked, and answered before. You obviously did not do that.

Secondly you need more detailed information to provide a viable response, such as the OS you are using and the version of Softice. Try "softice + Breakpoints" and/or "XP + breakpoints" and you will find a good analysis of prior questions and the reponses.

Regards.

BitBanger
February 14th, 2003, 16:17
Excuse me for the question. I found some information in previous posts about the subject. BTW i encountered this problem on win 98 with SI 9x v 4.05.334

BitBanger