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Xerxes35
2008-09-29, 13:41
Can somebody show me what

lim e^tanx
x->pi/2+

is please?

bobfish
2008-09-29, 16:37
Yes..

Xerxes35
2008-09-29, 16:46
Sorry the title meant to say limit question.

Xerxes35
2008-10-01, 03:29
So no one knows the answer to this question?

Lifejunkie where are you! lol

Shadout Mapes
2008-10-01, 03:46
just move the limit inside the exponent:

exp( lim(x-> pi/2+) tanx)

As you move from x = pi to x = pi/2 (this is what the + means right? it's been a while, i might be going in the wrong direction) tanx goes to -infinity. so now:

lim (x-> -infinity) e^x

i hope that simplifies the problem sufficiently

bobfish
2008-10-01, 15:08
Pi/2 has no tangent. Division by 0.

Shadout Mapes
2008-10-02, 06:09
Pi/2 has no tangent. Division by 0.

Which would be the purpose of taking the limit. Although it is an important distinction that a one-sided limit is usually necessary in the case where the denominator approaches zero for the limit to be defined.

SelfAdjoint
2008-10-02, 20:11
Since the exponential function is a continuous function, you can take the limit inside the exponent. Which gives you a divergent limit. Problem solved; the limit doesn't exist. If the limit approaches from the other side of pi/2, the limit is zero.