A deuteron (deuterium nuclei, basically the bound state of a proton and neutron) is struck by a photon and dissociates into a proton and a neutron, which both move off in the same direction, with respective speeds Vp and Vn (which are both a lot less than the speed of light). Calculate the minimum photon energy required given that the binding energy B = 2.224589 MeV.

Ephoton = Binding Energy + Kinetic Energy of the particles?

Shit, what about conservation of momentum?

Ephoton = Binding Energy + Kinetic Energy of the particles?

Shit, what about conservation of momentum?

Yeah, that was exactly my thinking.

I have the solution now, i'll post it up in a couple of days. It's quite a nice problem.

Hint: First show that the minimum energy is when Vp = Vn assuming Mp = Mn.